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$\frac{(6a + b)(a+ b) - 7b(a + b)}{2a^2 - 2b^2}$
combine like terms in the numerator
$\frac{6a^2 - 6b^2}{2a^2 - 2b^2}$
= $\frac{6(a^2 - b^2)}{2(a^2-b^2)}$ = $\frac{6}{2}$
= 3
johnmulu answered the question on March 9, 2017 at 06:58
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